Cubs beat the Indians in Game 7 thriller to win the World Series


CLEVELAND, OH – NOVEMBER 02: David Ross #3 of the Chicago Cubs celebrates with Jason Heyward #22 after hitting a solo home run during the sixth inning against the Cleveland Indians in Game Seven of the 2016 World Series at Progressive Field on November 2, 2016 in Cleveland, Ohio. (Photo by Jason Miller/Getty Images)

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CLEVELAND – The Chicago Cubs defeated the Cleveland Indians 8-7 early Thursday morning to claim their first World Series victory in more than 100 years.

Trailing three games to one in the series, the Cubs rallied to win games five, six and seven. On Wednesday, the Cubs were victorious in a thrilling extra-innings affair.

With the Cubs leading 6-4 in the eighth inning, Indians outfielder Rajai Davis hit a tying, two-run homer off closer Aroldis Chapman.

Davis yanked Chapman’s slider over the wall in the left-field corner with two outs in the eighth inning, capping a three-run inning and pulling the Indians even for the first time since the fourth inning.

The Cubs battled back in the 10th inning with Ben Zobrist putting them ahead 7-6 with a smash down the third base line. Catcher Miguel Montero singled to extend the lead to 8-6.

Rajai Davis struck again in the bottom of the 10th inning, cutting the lead to one before the Cubs finished them off to make history for Chicago.

This is the first World Series victory for the Cubs since 1908.  Prior to 2016, the Cubs’ last appearance in the World Series was in 1945.

The Cleveland Indians have not won the World Series since 1948.  Prior to 2016, the Indians last appeared in the World Series in 1997, when they lost to the Florida Marlins in seven games.

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